[Prev][Next][Index][Thread]
Re: Trombe wall efficiency
Steve Paschke <steve_paschke@msmgate.mrg.uswest.com> wrote:
>> Nick Pine <nick@vu-vlsi.ee.vill.edu> wrote:
>> Here's a small picture, a view from the East, say:
--------------- ^
132F <=O= <| | up 32F 311 Btu/hr/ft^2
| <| ^ | < --- Sun
| | ^<| |<-Polycarbonate plastic
| | <| ^ |
house | ^<|<--|--80% shadecloth
16' z z z i South
| <| ^ |
| |<--|---|--Original house wall (clear enough? :-)
| _<| ^ |
68F ==I====> |
-------------------------------------------
| 3" |
>Wouldn't black painted metal be better than shadecloth at absorbing heat
>and radiating the heat absorbed?
The idea here is that the cool air rises up through the passage between
the glazing and the shadecloth, moves ***through*** the shadecloth,
from right to left, becoming warmed in the process, as in the Conserval
wall, and goes back into the house at the top. If the black-painted metal
had no holes in it, it would probably not work as well as the shadecloth.
If it did, it might work better, like the Conserval wall.
>I've built a unit several years ago with painted beverage cans with mild
>success. I think that a large heat sink (made from scrap sheet metal)
>would be most effective.
Lots of absorbing surface area is nice, altho it's curious that
in a linear model, it looks like that doesn't matter at all.
Nick
References: